(y^2-5)(3y^2-4y+4)=

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Solution for (y^2-5)(3y^2-4y+4)= equation:


Simplifying
(y2 + -5)(3y2 + -4y + 4) = 0

Reorder the terms:
(-5 + y2)(3y2 + -4y + 4) = 0

Reorder the terms:
(-5 + y2)(4 + -4y + 3y2) = 0

Multiply (-5 + y2) * (4 + -4y + 3y2)
(-5(4 + -4y + 3y2) + y2(4 + -4y + 3y2)) = 0
((4 * -5 + -4y * -5 + 3y2 * -5) + y2(4 + -4y + 3y2)) = 0
((-20 + 20y + -15y2) + y2(4 + -4y + 3y2)) = 0
(-20 + 20y + -15y2 + (4 * y2 + -4y * y2 + 3y2 * y2)) = 0
(-20 + 20y + -15y2 + (4y2 + -4y3 + 3y4)) = 0

Combine like terms: -15y2 + 4y2 = -11y2
(-20 + 20y + -11y2 + -4y3 + 3y4) = 0

Solving
-20 + 20y + -11y2 + -4y3 + 3y4 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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